1/ Your car\'s fuel efficiency is e = 26 miles per gallon. The fuel pump pulls f

Question

1/ Your car's fuel efficiency is e = 26 miles per gallon. The fuel pump pulls fuel from the tank at the same speed vat which the car itself moves (so if the car is moving 1 mile per hour, the fuel moves through the pump at 1 miles per hour). The fuel pump pulls fuel at speed v through a hose with cross-sectional area A. What is the cross-sectional area of the hose in square inches? What is it in square millimeters? (1 gallon =231 in3. You need to find the volume of fuel pumped per time in terms of v and A Fuel efficiency is distance traveled per fuel pumped, which is equal to speed v divided by fuel pumped per time. The time dependence cancels out. Fuel efficiency has units distance per volume.)

please Show your work

Explanation / Answer

we know, 1 mile = 63360 inch

Let the car speed is 26 mile/hour

so, in our time it consumes 1 gallon of fuel.

so volume of the fuel pumped = A*v*t

1 gallon = A*(26 miles/hour)* 1hour

1 gallon = A*26 miles

231 in^3 = A*26*63360 in

A = 231/(26*63360) in^2

= 1.4*10^-4 in^2 <<<<<<<---------------Answer

we know, 1 1inch = 25.4 mm

so, A = 1.4*10^-4*(25.4)^2

= 0.09046 mm^2 <<<<<<<---------------Answer

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