need help. work out please 5. Bat-like Man is leapine from builaimeters belowe t
ID: 1396235 • Letter: N
Question
need help. work out please
Explanation / Answer
Ho = 15 m
u = 6.1 m/s
theta = 25 degrees
(a) Vertical component of initial velocity = u sin(theta) = 6.1 * sin (25 degrees) = 2.57 m/s
Horizontal component of initial velocity = u cos(theta) = 6.1 * cos (25 degrees) = 5.53 m/s
(b) t = ( u sin(theta) / g + sqrt( ( u sin(theta) / g )^2 - (2Ho/g))
t = (2.57/9.81) + sqrt((2.57/9.81)^2 - (2*15/9.81)) = 0.262 + 1.729 = 1.99 s
Time taken to land = 1.99 s
(c) Horizontal distance traveleld = u cos(theta) t = 5.53 x 1.99 = 11 m
(d) 11 m > 10 m
Hence Bat like man succeed in landing ( since 11 m > 10 m which is distance of next building )
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