Question Name: Vertical Oscillator4 A metal ball of mass m = 0.54 kg is hanging

Question

Question Name: Vertical Oscillator4 A metal ball of mass m = 0.54 kg is hanging from a vertical spring with elastic constant k = 20 N/m near the surface of the earth. In equilibrium, the spring is stretched by 10cm relative to the relaxed length of the spring. The spring is then compressed by 1 cm relative to the equilibrium position and is released into oscillation at time t = 0. The height of the object relative to the equilibrium height oscillates as shown below as a function of time. Analyze carefully pictures on the left and decide which one of the pictures describes oscillation amplitude as a function of time in the case when the oscillating body mass is quadrupled and all other parameters remain the same.

Explanation / Answer

Solution:

When mass is quadrupled, the frequency of oscillation reduces by half. As a result time period will be doubled.

So the oscillation amplitude will slow down.

answer: B

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