msatellite = 9000 kg earth- 6.37 x 106 m -6.67259 × 10-11 N m2/kg2 Rearth and Th
ID: 1397529 • Letter: M
Question
msatellite = 9000 kg
earth- 6.37 x 106 m -6.67259 × 10-11 N m2/kg2 Rearth and The radius of the satellite around the center of the Earth is r = 7 R, where R is the radius of the Earth. Hint: You may find it useful to take into account that the gravitational force is a con- servative force Hint: The universal gravitational force law 1S F=G Satellite Earth Caution: Neglect the rotational kinetic en- ergy due to the Earth's rotation. Find the energy required to launch a satel- lite from Earth into the circular orbit at the specified radius r = 7 R Answer in units of J.Explanation / Answer
Total energy require = GMm[1/R –1/2r]
where G = gravatataional constant
M = mass of satellite
m= mass of earth
R = radous of earth
r = radius of orbit
plugging the value = 6.67259 x 10^-11 x 5.98 x 10^24 x 9000 ( 1/ 6.37 x 10^6 - 1/ (14 x 6.37 x 10^6)= 52.35 x 10^10 J apprx
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