A rectangular coil of wire 22.0 cm by 35.0 cm and carrying a current of 1.80 A i

Question

A rectangular coil of wire 22.0 cm by 35.0 cm and carrying a current of 1.80 A is oriented with the plane of its loop perpendicular to a uniform 1.70 T magnetic field, as shown in the figure (Figure 1) .

Part A

Calculate the net force that the magnetic field exerts on this coil.

F = ____ N

Part B

Calculate the torque that the magnetic field exerts on this coil.

= ____ Nm

Part C

The coil is now rotated through a 30.0 0o angle about the axis shown, the left side coming out of the plane and the right side going into the plane. Calculate the net force that the magnetic field exerts on the coil. (Hint: In order to help visualize this three-dimensional problem, make a careful drawing of the coil as viewed along its axis of rotation.)

F = ______ N

Part D

Calculate the torque that the magnetic field exerts on the coil in part (C).

= _____ Nm

Explanation / Answer

A) Net force is zero.

Beacuse, force on upper and lower segments are equal and acts opposite direction.

force on left and right segments are equal and acts opposite direction.

B) T = N*I*A*B*sin(theta)

here, N is no of loops, I is current, A is area of loop and B is magnetic field.

theta is the angle between normal to the loop and magnetic field.

T = N*I*A*B*sin(0)

= 0

C) In this case also Net force is zero.

Beacuse, force on upper and lower segments are equal and acts opposite direction.

force on left and right segments are equal and acts opposite direction.

D)
T = N*I*A*B*sin(theta)

= 1*1.8*0.22*0.35*1.7*sin(30)

= 0.118 N.m

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