The figure shows a 4.0 cm diameter loop with resistance 0.10 n around a 2.0 cm d

Question

The figure shows a 4.0 cm diameter loop with resistance 0.10 n around a 2.0 cm diameter solenoid. The solenoid is 10 cm long, has 100 turns, and carries the current shown in the graph. A positive current is counterclockwise when seen from the left. 1st (A) 20 t (s) 2.0 cm 4.0 cm 1 12 3 a) Find the magnetic field inside the solenoid at 1.0 s b) The magnetic flux in the cross-sectional area of the solenoid at 1.0 s c) The electromotive force induced in the loop at t 1.5 s d) The electric current in the loop t 1.5 s.

Explanation / Answer

Here ,

a) for the solenoid ,

magnetic field inside solenoid , B = u0*N*I/L

B = u0*100 * 20/(0.10)

B = 0.0251 T

the magnetic field inside the solenoid is 0.0251 T

b)

flux = area * field .

magnetic flux = pi*0.01^2 * 0.0251

magnetic flux = 7.89 *10^-6 Wb

the magnetic flux is 7.89 *10^-6 Wb

c)

Now ,

emf induced in the loop = change in flux /time

emf induced in the loop = 7.89 *10^-6 *(1 - (-1))/1

emf induced in the loop = 1.58 *10^-5 V

the emf induced in the loop is 1.58 *10^-5 V

d)

current in the loop = induced emf/R

current in the loop = 1.58 *10^-5/.10

current in the loop = 1.58 *10^-4 A

the induced current in the loop is 1.58 *10^-4 A

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