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1) At time t = t 1 = 0.018 s, what is I 1 , the induced current in the loop? I 1

ID: 1398804 • Letter: 1

Question

1)

At time t = t1 = 0.018 s, what is I1, the induced current in the loop? I1 is defined to be positive if it is in the counterclockwise direction. -0.0243 A

2)

At time t = t2 = 0.411 s, what is I2, the induced current in the loop? I2 is defined to be positive if it is in the counterclockwise direction.

3)

What is Fx(t2), the x-component of the force that must be applied to the loop to maintain its constant velocity v = 50 cm/s at t = t2 = 0.411 s?

4)

At time t = t3 = 0.338 s, what is I3, the induced current in the loop? I3 is defined to be positive if it is in the counterclockwise direction.

5)

Consider the two cases shown above. How does II, the magnitude of the induced current in Case I, compare to III, the magnitude of the induced current in Case II? Assume s2 = 3s1.

II < III

II = III

II > III

Explanation / Answer

2.

At this point, the loop is tring to exit the field, with the s2 part of the square still inside the field.

By Faraday's law, as the flux out of the page is decreasing, the loop must "help" it.

Thus, an induced current that is COUNTERCLOCKWISE must be produced.

The emf induced is

emf = B v s2

emf = 0.0504 V

Thus, the current is

I = emf /R = 0.0504 A, (positive as it is counterclockwise) [ANSWER]

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3.

The force needed to counter the force of the field is

F = B I s2 = 5.08*10^-3 N [ANSWER]