Please answer all last post 1.A +67 ? C charge is placed 39 cm from an identical

Question

Please answer all last post

1.A +67 ?C charge is placed 39 cm from an identical +67 ?C charge. If you assume the potential at infinity is zero, then what is the potential midway between the two charges?

How much work is done to move a 0.60 ?C charge from a point midway between the charges to a point 10 cm closer to either of the charges?

What is the electric potential at point F?

What is the magnitude of the electric field at point B?

3.In the diagram, q1 is 5.70 nC, q2 is 8.90 nC, q3 is 1.80 nC, and q4 is 5.70 nC. The distance d is 6.30 mm. Find the potential at point A in the diagram, at the center of the square. Assume that V = 0 at infinity.

Find the potential at B.

Find the potential at C.

3.

Explanation / Answer

Here ,

charge , q = + 67 uC

distance , d = 0.39/2

d = 0.195 m

Now, potential due to a charge is given as

V = k*q/d

potential between the charges = 2 * 9*10^9 * 67 *10^-6/.195

potential between the charges = 6.185 *10^6 V

the potential between the charges is 6.185 *10^6 V

Now , at a point 10 cm closer to eaither charge

potential , V2 = 9*10^9 * 67 *10^-6 *(1/0.095 + 1/0.295)

V2 = 8.391 *10^6 V

work done in moving charge = q *( V2 - V1 )

work done in moving charge = 0.60 *10^-6 * (8.391 *10^6 - 6.185 *10^6 )

work done in moving charge = 1.324 J

the work done in moving charge is 1.324 J

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