A parallel plate capacitor with adjustible plate separation d and adjustible are

Question

A parallel plate capacitor with adjustible plate separation d and adjustible area A is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V Volts. (C is the capacitance and U is the stored energy.) Give all correct answers concerning a parallel-plate capacitor charged by a battery (e.g. B, AC, CDF).

A) After being disconnected from the battery, increasing the area A will increase V.
B) With the capacitor connected to the battery, increasing the area A will increase U.
C) With the capacitor connected to the battery, decreasing d increases C.
D) After being disconnected from the battery, increasing the area A will increase C.
E) After being disconnected from the battery, increasing d decreases V.
F) After being disconnected from the battery, increasing d increases U.

I need the correct answer in order to rate.

Explanation / Answer

A) after disconnecting Q is constant

then V = Q/C

by increasing A then C increasesthen automatically V decreases ............So A is False

B) U = 0.5*C*V^2

connected to battery V is constant ,by increasing A increases C
then U increases ............So B is True

C) V is constant....

C = eo*A/d.....by decreasing d,increases C....true

D) C = eo*A/d =

by increasing A ,then C increases....True

E) After disconnecting Q is constant

V = Q/C

as d increases then C decreases,thereby V increases...False

F) U = Q^/(2*C)

increasing d then C decreses,hence U increases....True

So true statements are BCDF

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