Two long, parallel conductors, separated by 13.0 cm, carry currents in the same

Question

Two long, parallel conductors, separated by 13.0 cm, carry currents in the same direction. The first wire carries a current I1 4.00 A, and the second carries 12 8.00 A. (See figure below. Assume the conductors lie in the plane of the page (a) What is the magnetic field created by I1 at the location of I? magnitude 61.5e-05 x What is the equation giving the magnetic field of a long, straight, current-carrying wire? T direction in the +y direction v (b) What is the force per unit length exerted by I1 on 12? N/m magnitude direction Select (c) What is the magnetic field created by I2 at the location of I1? magnitude direction Select (d) What is the force per length exerted by I2 on T1? N/m magnitude direction Select

Explanation / Answer

the formual for magnetic field due to long stright wire carry current is

B = o / 2 ) ( I / r )

(a)

the magnetic field created by I1 at the location I2 is

B1 = ( o / 2 ) ( I1 / r )

      = 2 x 10^-7 * ( 4A/ 0.13 m )

      = 6.153x 10^-6 T

the direction is +ve z-direction ( out of the page)

(b)

the force per unit lenght exerted by I1 on I2 is

F2 /L= ( o / 2 ) ( I1 I2/ r )

      = 2x 10^-7 * 8A(4A)/ 0.13 m

      = 4.92 x 10^-5 N

Direction: -ve y direction

(c)

the magnetic field created by I2 at the location I1 is

B2 = ( o / 2 ) ( I2 / r )

      = 2 x 10^-7 * ( 8 A/ 0.13 )

      = 1.23x 10^-5 T

the Direction of magnetic field is -ve z-direction ( into the page)

(d)

the force per unit lenght exerted by I2 on I1 is

F2 /L= ( o / 2 ) ( I1 I2/ r )

      = 2x 10^-7 * 8A(4A)/ 0.13 m

      = 4.92 x 10^-5 N

the direction of force is +ve y direction

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