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Chrome File Edit View History Bookmarks People Window Help 'N 2 ò X a 100% E Tue 7:44 PM Jasmin Ramirez Bonilla a E MasteringPhysics: HW07: Current& Circuits https://session.masteringphysics.com/myct/itemView?assignmentProblemID-49725220 4 h Physics 19-01, Summer 2015, UC Merced Signed in as Jasmin RamirezBonilla Help Close urren Problem 25.48 Resources « previous 11 of 16 next» Problem 25.48 Part A In the circuit of the figure (Figure 1), find the current supplied by the battery Ie2.87 A Submit My Answers Give Up Correct Figure 1 of 1 Part B Find the current through the 6- resistor 1 2 mA Submit My Answers Give Up Incorrect; One attempt remaining; Try Again .png ovide Feedback Continue

Explanation / Answer

Here ,

For 2 ohm , 4 ohm and 6 ohm in parallel ,

1/Rp = 1/2 + 1/4 + 1/6

Rp = 1.090 Ohm

Now , for Rp and 1 Ohm in series ,

Req = 1 + 1.090

Req = 2.090 Ohm

Now, using ohm's law

Ieq = 6/2.090

Ieq = 2.87 A

the equivalent current in the battery is 2.87 A

part B)

Now , voltage across 6 ohm = 6 - 1 * 2.87

voltage across 6 ohm = 3.14 V

Now, current in 6 Ohm = 3.14/6

current in 6 Ohm = 0.522 A

the current in 6 Ohm is 0.522 A

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