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For problems 6-8 use the following: A bullet with a mass of 9.0 g moving horizon

ID: 1400758 • Letter: F

Question

For problems 6-8 use the following: A bullet with a mass of 9.0 g moving horizontally strikes a very heavy block of wood resting on a rough surface, and penetrates a distance of 5.0 cm and stops inside the block. The speed of the bullet just before the collision is 645 m/s. 6. (4 points) The momentum of the bullet-block system before the collision is 5.8 kg m/s b, 45 kg m/s c.. 5800 kg m/s d. 645 m/s e. cannot be determined, the mass of the block is required 7. (5 points) The average force that the wood exerted on the bullet was approximately 0 N 3.75 x 10 N c. 3.75 x 10 N d. Unknown; the mass of the block is required ooQ e. None of these is correct 8. (4 points If the block doesn't move at all, what can be said about the momentum of the bullet- block system after bullet hits the block? a. The momentum is conserved b. The momentum is greater than before the collision c. The momentum is less than before the collision d. Impossible to tell; the mass of the block is required e. None of these is correct

Explanation / Answer

Here ,

speed of bullet , u = 645 m/s

mass of bullet , mB = 0.009 Kg

6)

momentum before collision = mB*u

momentum before collision = 0.009 * 645

momentum before collision = 5.805 Kg.m/s

7)

Now, let the force acting is F

using work energy theroum

F*0.05 = 0.5 * 0.009 * 645^2

solving for F

F = 3.75 *10^4 N

the force acting on the bullet is 3.75 *10^4 N

8)

as there is friction acting on the block ,

c) the momentum is less than before the collision