The following four problems are about the following situation: Uranium-238 goes
ID: 1401247 • Letter: T
Question
The following four problems are about the following situation: Uranium-238 goes through an alpha decay, then two beta decays, and finally another alpha decay. What element is left after each decay (in order):
5) After the first a decay:
U-238
U-234
Pa-234
Th-234
Th-230
6) After the first b decay:
U-238
U-234
Pa-234
Th-234
Th-230
7) After the second b decay:
U-238
U-234
Pa-234
Th-234
Th-230
8) After the second a decay:
U-238
U-234
Pa-234
Th-234
Th-230
9) Which of the following types of radiation has no mass and no charge?
alpha
beta
gamma
Explanation / Answer
here ,
for U - 238
5)
after the first deacy , alpha decay
atomic number = 92 - 2 = 90
atomic mass = 238 - 4 = 234
Hence , the product is Th- 234
6)
after the first b - decay ,
as the electrons are ejected in beta -decay
atmoic number = 90 + 1 = 91
as the atomic mass is same
the product is Pa-234
7)
after the second beta - decay
as the electrons are ejected in beta -decay
atmoic number = 91 + 1 = 92
as the atomic mass is same
the product is U-234
8)
after the seconf alpha deacy , alpha decay
atomic number = 92 - 2 = 90
atomic mass = 234 - 4 = 230
Hence , the product is Th- 230
9)
as the gamma radiations are EM radiations
hence , the gamma radiation have no mass and no charge
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