The 5.05 A current through a 1.50 H inductor is dissipated by a 1.89 resistor in
ID: 1401444 • Letter: T
Question
The 5.05 A current through a 1.50 H inductor is dissipated by a 1.89 resistor in a circuit like that in the figure below, with the switch in position 2.
(a) What is the initial energy in the inductor?
19.127 J This answer is correct
(b) How long will it take the current to decline to 5.00% of its initial value?
2.378 s This answer is correct
(c) Calculate the average power dissipated, and compare it with the initial power dissipated by the resistor.
Pavg
I NEED HELP WITH PART C PLEASE!!!
Pavg =What is the energy when the current is 5.00% of the initial current? How is average power defined in terms of initial and final energies? W Pi
Pavg
I NEED HELP WITH PART C PLEASE!!!
=What is the energy when the current is 5.00% of the initial current? How is average power defined in terms of initial and final energies?
Explanation / Answer
(c) Average energy dissipated would be through the resistor
Pav = Irms2 R
Pav = [5.05/sqrt(2)]2 (1.89)
Pav =(5.05)2 (1.89) / 2
Pav = 24.1 W
Average power dissipated =24.1 W
And initially current flowing through resistance was I = 5.05 A
so initial power dissipated was Pi = (5.05)2(1.89)
Pi = 48.2
So it initial power dissipated would be twice of average power dissipated
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