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2. (10pts) A 4.63 kg mass is sliding to the right at a constant velocity of 7.96

ID: 1401753 • Letter: 2

Question

2. (10pts) A 4.63 kg mass is sliding to the right at a constant velocity of

7.96 m/s across a horizontal surface while being pulled by the two forces

shown in the drawing plus an unknown friction force. The rope with a

tension T of 23.5 N acts to the left and a force F of 48.4 N acts to the

right at an angle of 27.8 above horizontal.

(a) (5pts) Draw a free-body diagram for this problem, being careful to

show all forces in terms of their components.

(b) (5pts) Determine the coefficient of friction () between the object and

the surface.

Explanation / Answer

Horizontal force is F*cos(27.8)-T = (48.4*cos(27.8)) – 23.5 = 19.3 N

Since the body was moving with conastnt speed hence accelarationa = 0 m/s^2

then if the body is moving to the right then the frictional force is along left

Friction force is f = 19.3 N

then f = mu_k*m*g

coefficient f kinetic friction is mu_k = f/(m*g) = 19.3/(4.63*9.81) = 0.424

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