1) Using Faraday\'s Law, calculate the induced emf around the loop in the figure

Question

1) Using Faraday's Law, calculate the induced emf around the loop in the figure that is caused by the changing flux. Assign clockwise to be the positive direction for emf.

2) The emf around the loop causes a current to flow. How large is that current? (Again, use a positive value for clockwise direction.)

3) From your previous results, what must be the electrical resistance of the loop? (The resistance of the rails is negligible compared to the resistance of the rod, so the resistance of the loop is constant.) Use units of Ohm.

4) The rate at which the external force does mechanical work must be equal to the rate at which energy is dissipated in the circuit. What is that rate of energy dissipation (power dissipated)?

Since the answers has 4 parts, I opened 2 questions for it. You can give the answers to 3 & 4 here, and 1 & 2 on the other page here: https://www.chegg.com/homework-help/questions-and-answers/next-four-questions-refer-situation-conducting-rod-pulled-horizontally-constant-force-f-42-q7952327 .

Explanation / Answer

1) induced emf = B*v*d

= 0.7*4.5*0.62

= 1.953 volts (anti closkwise)

= -1.953 volts

2) Apply, F*V = induced emf*induced current

induced current = F*v/induced emf

= 4.2*4.5/1.953

= -9.68 A

3) R = induced emf/induced current

= 1.953/9.68

= 0.202 ohms

4) rate of energy dissipation = F*v
= 4.2*4.5

= 18.9 Watts

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