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need help ASAP please help! The 10-cm-wide, zero-resistance slide wire shown in

ID: 1402021 • Letter: N

Question

need help ASAP please help!

The 10-cm-wide, zero-resistance slide wire shown in the figure is pushed toward the 2.0? resistor at a steady speed of 0.50 m/s. The magnetic field strength is 0.20 T .
(Figure 1)

Part A

How big is the pushing force?

Express your answer with the appropriate units.

Part B

How much power does the pushing force supply to the wire?

Express your answer with the appropriate units.

Part C

What is the magnitude of the induced current?

Express your answer with the appropriate units.

Part D

What is the direction of the induced current?

Part E

How much power is dissipated in the resistor?

Express your answer with the appropriate units.

clockwise counterclockwise

Explanation / Answer


emf induced = e = B*v*L


induced current i = e/R = B*v*L/R


force exerted by the magnetic field on current carrying slide Fb = i*L*B = B*v*L/R*L*B = B^2*L^2*v/R

as the slide is moving with constant speed push = Fb


part(A)

push = (0.2^2*0.1^2*0.5)/2 = 0.0001 N <<<--answer

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part(B)

power = F*v = 0.00005 W

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part(C)

i = B*v*L/R = (0.2*0.5*0.1)/2 = 0.005 A <<-----answer


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part(D)

from lenz law

as the rod moves towards the right the magnetic flux
decreases.so, the indued current is in counterclockwise to
oppose the decrease


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part(E)


power dissipated = i^2*R = 0.00005 W