need help ASAP please help! The 10-cm-wide, zero-resistance slide wire shown in
ID: 1402021 • Letter: N
Question
need help ASAP please help!
The 10-cm-wide, zero-resistance slide wire shown in the figure is pushed toward the 2.0? resistor at a steady speed of 0.50 m/s. The magnetic field strength is 0.20 T .
(Figure 1)
Part A
How big is the pushing force?
Express your answer with the appropriate units.
Part B
How much power does the pushing force supply to the wire?
Express your answer with the appropriate units.
Part C
What is the magnitude of the induced current?
Express your answer with the appropriate units.
Part D
What is the direction of the induced current?
Part E
How much power is dissipated in the resistor?
Express your answer with the appropriate units.
clockwise counterclockwiseExplanation / Answer
emf induced = e = B*v*L
induced current i = e/R = B*v*L/R
force exerted by the magnetic field on current carrying slide Fb = i*L*B = B*v*L/R*L*B = B^2*L^2*v/R
as the slide is moving with constant speed push = Fb
part(A)
push = (0.2^2*0.1^2*0.5)/2 = 0.0001 N <<<--answer
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part(B)
power = F*v = 0.00005 W
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part(C)
i = B*v*L/R = (0.2*0.5*0.1)/2 = 0.005 A <<-----answer
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part(D)
from lenz law
as the rod moves towards the right the magnetic flux
decreases.so, the indued current is in counterclockwise to
oppose the decrease
---------
part(E)
power dissipated = i^2*R = 0.00005 W
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