Problem 2: The intensity of an electromagnetic wave is I = 740 W/m2. Randomized

Question

Problem 2: The intensity of an electromagnetic wave is I = 740 W/m2.

Randomized Variables I = 740 W/m2

Part (a) Find the average energy density per unit volume, Uave, in terms of I and the speed of light c. Expression :

Uave = __________________________________________

Select from the variables below to write your expression. Note that all variables may not be required.

, , 0, , c, d, g, h, i, I, j, m, P, t, Uavg

Part (b) Solve for the numerical value of Uavg in J.

Numeric : A numeric value is expected and not an expression.

Uavg = __________________________________________

Part (c) Find an equation for the square of the maximum magnitude of the magnetic field of the wave in terms of Uavg and the permeability of free space 0.

Expression :

Bmax2 = __________________________________________

Select from the variables below to write your expression. Note that all variables may not be required.

, , 0, , c, d, g, h, i, I, j, m, P, t, Uavg

Part (d) Solve for the numerical value of Bmax in tesla.

Numeric : A numeric value is expected and not an expression.

Bmax = __________________________________________

Explanation / Answer

part a:

as we know, the energy density Uave of an electromagnetic wave and its intensity I are related by

I=c*Uave

==> Uave=I/c

part b:

as I=740 W/m^2 and c=3*10^8 m/s

Uave=I/c=740/(3*10^8)=2.4667*10^(-6) J

part c:

as we know, energy density Uave and magnetic field strength B are related by

Uave=B^2/mu

where mu=4*pi*10^(-7)

B^2=mu*Uave

part d:

putting the values of different symbols,

we get Bmax=1.7606*10^(-6) tesla

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