1. -1 points SerPSE9 37.P005.WI My Notes Young\'s double-slit experiment is perf
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1. -1 points SerPSE9 37.P005.WI My Notes Young's double-slit experiment is performed with 547-nm light and a distance of 2.00 m between the slits and the screen. The tenth interference minimum is observed 7.44 mm from the central maximum. Determine the spacing of the slits. Need Help? Read It Watch It -2 p ts SerPSE9 37. R009.MI.FB. My Notes A pair of narrow, parallel slits separated by 0.230 mm is illuminated by green light (a 546.1 nm). The interference pattern is observed on a screen 1.40 m away from the plane of the parallel slits. (a) Calculate the distance from the central maximum to the first bright region on either side of the central maximum. b) Calculate the distance between the first and second dark bands in the interference pattern. Need Help? Read It l Master It -4 p ts SerPSE9 37. R021.WI My Notes In the double-slit arrangement of the figure below, d 0.150 mm, L 69 cm, h 643 nm, and y 1.19 cm. Viewing screen. (a) What is the path difference for the rays from the two slits arriving at P? b) Express this path difference in term of A. (c) Does P correspond to a maximum, to a minimum, or an intermediate condition?Explanation / Answer
Sorry we are allowed to solve one question at a time .
(1) We know that
Y= ((n+1/2)D*lambda)/d where d is spacing
lambda is wavelength
and Y is the distance from centre fringe
Y = 7.44 mm
D = 2 m
and wavelength = 547 nm (please check the value because it is quite invisible)
so d = 21D*lambda/2Y
d = 1.543 mm
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