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DAT 4))) 100% Sat 11:12 PM € Chrome File Edit View History Bookmarks People Wind

ID: 1403459 • Letter: D

Question

DAT 4))) 100% Sat 11:12 PM € Chrome File Edit View History Bookmarks People Window Help VA Hww11 JJ5521 c Chegg C https:/ ne /www.webassign t/web/Student/Assignment-Responses/Mast?dept 654270#Q3 E App A&M; Organizations TCC Miscellaneous PT WTC E Sch onli Additional Materials Reading 10. 0/1 points I Previous Answers OSColPhys1 2.2.019 My Notes Ask Your Teacher If the pressure reading of your Pitot tube is 10.0 mm Hg at a speed of 250 km/h, what will it be at 700 km/h at the same altitude? 178 X mm Hg Additional Materials Reading 11. 1/1 points I Previous Answers OSColPhys1 2.2.02 My Notes Ask Your Teacher Every few years, winds in Boulder, Colorado, attain sustained speeds of 45.0 m/s (about 100 miles per hour) when the jet stream descends during early spring. Approximately what is the force due to the Bernoulli effect on a roof having an area of 250 m2? Typical air density in Boulder is 1.14 kg/m3, and the corresponding atmospheric pressure is Bernoulli's principle as stated in the text result, because there is significant N/m assumes laminar flow. Using the principle here produces only an approximate 8.89 turbulence.) 289.000 N Additional Materials

Explanation / Answer

from bernoullis theorem


P1 + 0.5*rho*v1^2 = P2 + 0.5*rho*v2^2


P1 = 10 mm of Hg = 10*10^-3*13600*9.8 = 1332.8 pa


v1 = 250 km / h = 250*(5/18) = 69.44 m/s


v2 = 700 km / h = 194.4 m/s

P2 = P1 + 0.5*rho*v1^2 - 0.5*rho*v2^2


P2 = (1332.8)+(0.5*1.2*69.44^2)-(0.5*1.2*194.4^2)


P2 = 138 mmof Hg