v grows as well v stays constant v grows but then stops growing v oscillates Equ
ID: 1403618 • Letter: V
Question
v grows as well
v stays constant
v grows but then stops growing
v oscillates
Equation 2: T = 2(L/g)1/2 (pendulum equation)
What would happen to the period of a pendulum if the strength of gravity were to increase?
it would fluctuate
it would lengthen (take more time)
it would shorten (take less time)
it would not change
What happens to the period of a pendulum if you double the length of the cord and make gravity only half as strong?
it will become half as long
it will quadruple
it will double
nothing, it will not change
p = gd (pressure change with depth in a fluid)
where p = pressure, = density, g = gravitational acceleration and d = depth.
Which of the following doesn’t matter concerning the pressure you feel in the water of a swimming pool?
the density of the water
the Earth's gravity
the shape of the pool
how deep under the surface you are
p = gd (pressure change with depth in a fluid)
…where p = pressure, = density, g = gravitational acceleration and d = depth.
the pressure you experience will fluctuate
you will experience no change in pressure
you will experience a decrease in pressure
you will experience an increase in pressure
p = gd (pressure change with depth in a fluid)
…where p = pressure, = density, g = gravitational acceleration and d = depth.
it doubles
it triples
it stays the same
it increases by a factor of 12
: F = Gm1m2/d2 (Newton’s Law of Gravity, the gravitational attraction between two objects)
…where G is the gravitational constant, m1 is one of the masses, m2 is the other mass and d is the distance between the centers of the two objects.
the distance between the centers of the objects
the mass of one of the objects
the mass of the other object
the color of the objects
Explanation / Answer
1)
as t grows
v grows as well <-asnwer
Equation 2: T = 2(L/g)^1/2 (pendulum equation)
it would shorten (take less time)
3)
T2/T1 = sqrt(L2*g1/L1*g2)
L2 = 2l1
g2 = g1/2
T2/T1 = sqrt(2L1*g1/L1*2*g1)
T2 / T1 = sqrt(4) = 2
T2 =2T1
it will double
4)
p = gd (pressure change with depth in a fluid)
where p = pressure, = density, g = gravitational acceleration and d = depth.
the shape of the pool
5)
p = gd (pressure change with depth in a fluid)
…where p = pressure, = density, g = gravitational acceleration and d = depth.
you will experience an increase in pressure
6)
p = gd (pressure change with depth in a fluid)
…where p = pressure, = density, g = gravitational acceleration and d = depth.
p2/p1 = 2g2d2/1g1d1
d1 = 1m
d2 = 2m
2 = 31
g2 = 2g1
p2/p1 = 3*2*2 = 12
it increases by a factor of 12
+++++++++++++++++++
: F = Gm1m2/d2 (Newton’s Law of Gravity, the gravitational attraction between two objects)
…where G is the gravitational constant, m1 is one of the masses, m2 is the other mass and d is the distance between the centers of the two objects.
the color of the objects
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