The graph shows the US Department of Labor noise regulation for working without

Question

The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 82.0 dB.

1. Calculate the INCREASE in the sound level from the ambient work environment level (in dB).

2.A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 118 dB. By what factor does that sound intensity exceed the 1- Hours/day intensity limits from the graph?

Explanation / Answer

1) Adding a sound level of 85 dB and a sound level of 82 db gives a total level of 86.764 dB.
So, 10 log (10^8.5 + 10^8.2) = 86.764 dB increase in sound level

2) 1 hour/day sound level is 100 dB
Rock concert sound level is 118 dB

118dB - 100dB = 18dB

10^1.8= 63.095

The factor that exceed the 1 hour/day limit is 63.095.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.