Point charge q 1 = -5.00 nC is at the origin and point charge q 2 = +3.00nC is o

Question

Point charge q1 = -5.00 nC is at the origin and point charge q2 = +3.00nC is on the x -axis at x= 3.00cm. Point P is on the y-axis at y = 4.00cm.

A)

Calculate the electric fields E 1 and E 2 at point P due to the charges q1 and q2. Express your results in terms of unit vectors (see example 21.6 in the textbook).

A) Express your answer in terms of the unit vectors i^, j^. Enter your answers separated by a comma. Express your answer in terms of the unit vectors i^, j^. Enter your answers separated by a comma.

B) Use the results of part (a) to obtain the resultant field at P, expressed in unit vector form.

Explanation / Answer

a)

here ,

q1 = -5 nC

q2 = +3 nC

electric field , E1 = k * q1/d^2 i

E1 = 9*10^9 * 5 *10^-9/0.04^2 (-j)

E1 = - 28125 j N/C

due to second charge

E2 = k * q2/d^2 *( - 0.6 i + 0.8 j)

E2 = 9 *10^9 * 3 *10^-9/.05^2 *(- 0.6 i + 0.8 j)

E2 = -6480 i + 8640 j

elctric field is

E1 = - 28125 j N/C

E2 = -6480 i + 8640 j N/C

B)

Enet = - 28125 j -6480 i + 8640 j

Enet = - 6480 i-19485 j

the net electric field is -6480 i-19485 j

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