Three charged marbles are glued to a nonconducting surface and are placed in the
ID: 1404871 • Letter: T
Question
Three charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q1 = 6.30 µC, q2 = 1.03 µC, and
q3 = 2.28 µC.
Marble q1 is a distance r1 = 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance r' = 1.00 cm to the left of the center marble.
_______________ N/C
Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of
3.90 µC,
calculate magnitude and direction of the force on it.
___________________ N
___________________ N
Explanation / Answer
1. Given that :
charge on q1 = 6.3 x 10-6 C
charge on q2 = 1.03 x 10-6 C
charge on q3 = - 2.28 x 10-6 C
marble q1 has a distance, r1 = 3 cm = 0.03 m
marble q3 has a distance, r3 = 2 cm = 0.02 m
magnitude of the electric field at a distance, (r' = 0.01 m) to the left of the center marble which is given as ::
Using an equation, E = k Q / r2
Er' = k [q1 / (r1 - r')2 + q2 / (r')2 + q3 / (r3 + r1)2 { eq.1 }
where, k = constant = 9 x 109 Nm2/C2
inserting all these values in above eq.
Er' = (9 x 109 Nm2/C2) [(6.3 x 10-6 C) / (0.02 m)2 + (1.03 x 10-6 C) / (0.01 m)2 - (2.28 x 10-6 C) / (0.03 m)2]
Er' = (9 x 109 Nm2/C2) [(6.3 x 10-6 C) / (0.0004 m2) + (1.03 x 10-6 C) / (0.0001 m2) - (2.28 x 10-6 C) / (0.0009 m2)]
Er' = (9 x 109 Nm2/C2) [(15750 x 10-6 C/m2) + (10300 x 10-6 C/m2) - (2533.3 x 10-6 C/m2)
Er' = (9 x 109 Nm2/C2) (23516.7 x 10-6 C/m2)
Er' = 211650.3 x 103
Er' = 2.11 x 108 N/C
2. Another marble is placed (0.01 m) to the left of the middle marble.
magnitude of the force, F = q E { eq.2 }
where, q = - 3.9 x 10-6 C
inserting the values in eq.2,
F = (3.9 x 10-6 C) (2.11 x 108 N/C)
F = 8.229 x 102 N
F = 823 N
And the direction is "to the left" or in -ve x-direction.
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