Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Safari File Edit View History Bookmarks window Help Search in Document 100% Docu

ID: 1405213 • Letter: S

Question

Safari File Edit View History Bookmarks window Help Search in Document 100% Document Elements Tables Charts SmartArt Review A Home Layou Paragrap AaBbCcDdEt No spacing Heading 1 Heading 2 Subtitle subtle Empha... Emphasis Intense Emph Intense Quote Subtle Refere... Strong Text Box Shape Picture Themes chapter 15 for credit CA www.webassign.net seaworld Apple DressLily God help th... deviantART Disney ESPN Wikipedia Yahoo! Google News Facebook Physics question I chegg.com in 5. -4 points SerCP9 15.P.024 My Notes Ask Your Teacher BuC (a) Three point charges, A 1.70 HC, B 6.70 HC, and C -4.70 HC, are located at the corners of an equilateral triangle as in the figure above. Find the magnitude and direction of the electric field at the position of the 1.70 HC charge. magnitude (counterclockwise from the +x-axis) direction (b) How would the electric field at that point be affected if the charge there were doubled? The magnitude of the field would be halved. O The field would be unchanged. The magnitude of the field would double. O The magnitude of the field would quadruple. (c) Would the magnitude of the electric force be affected? O Yes

Explanation / Answer

a) Electric field at A due to B

Eb = kqB / r^2 = 9 x 10^9 x 6.70 x 10^-6 / 0.5^2

Eb = 241200 N/C

direction = 180 + 60 = 240 degrees from x-axis

Eb = 241200 ( cos240 i + sin240 j)

due to C

Ec = 9 x 10^9 x 4.70 x 10^-6 / 0.5^2 = 169200 N/C

direction towards +vs x-axis

Ec = 169200i N/C

Enwt = Ea + Ec = 48600i - 208885.33j N/C

magnitude = sqrt((48600)^2 + ( - 208885.33)^2) = 214464.55 N/C

direction = 360 - tan-1(208885.33 / 48600) = 283.10 degrees


b) if charges are doubled,

E = kq / r^2

so E will get doubled.


c) F = qE

So yes , it will be affected

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote