(8c21p7) Two identical conducting spheres, fixed in place, attract each other wi

Question

(8c21p7) Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.4171 N when separated by 50 cm, center-to-center. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.0109 N. What were the initial charges on the spheres? Since one is negative and you cannot tell which is positive or negative, there are two solutions. Take the absolute value of the charges and enter the smaller value here. Enter the larger value here.

Explanation / Answer

here,

let the charge on two sphere be q1 and q2

distance between the charges , d = 50 cm

d = 0.5 m

force = - 0.4171 N

k * q1 * q2 /d^2 = - 0.4171   

9 * 10^9 * q2*q1/0.5^2 = - 0.4171 ...(1)

after touching , both the sphere has same charge q = (q1 + q2)/2 ...(2)

force between charges , f' = 0.0109 N

k * q^2/d^2 = 0.0109

9 * 10^9 *q^2/0.5^2 = 0.0109 ....(3)

solving the equation (1) , (2) and (3)

we get

q1 = - 2.92 * 10^-6 C and q2 = 3.97 * 10^-6 C

or

q1 = 3.97 * 10^-6 and q2 = - 2.92 * 10^-6 C

taking the absolute value

the absolute value of the charges is 3.97 * 10^-6 , - 2.92 * 10^-6 C

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