You have two disks, 1 and 2, both of radius R = 24.0 mm and both made of the sam

Question

You have two disks, 1 and 2, both of radiusR = 24.0 mm and both made of the same nonconducting material. Disk 1 carries a uniformly distributed charge q1 = 1.50 C , and the uniformly distributed charge q2 on disk 2 is unknown. You place disk 1 at z1 = 0 and disk 2 atz2 = 32.0 mm such that the symmetry axis of each disk coincides with the z axis. Using a small charged pith ball, you locate one position on the zaxis where the electric force exerted on the pith ball is zero; this position is zE=0 = +88.0 mm.

What is the charge on disk 2?

Explanation / Answer

here,

radius of disks , r = 24 mm

r = 0.024 m

charge on disk 1 is q1 = 1.5 uC

q1 = 1.5 * 10^-6 C

z1 = 0

let the charge on disk 2 be q2

z2 = 32 mm

z2 = 0.032 m

electric feild at z3 = 88 mm

z3 = 0.088 mm

net elctric feild at Z3 is 0

K * Q *x1/(x1^2 + r^2)^1.5 - K * Q *x2/(x2^2 + r^2)^1.5 = 0

Q1*x1/(x1^2 + r^2)^1.5 = Q2 *x2/(x2^2 + r^2)^1.5

1.5 * 10^-6*0.088/(0.088^2 + 0.024^2)^1.5 = Q2 *0.056/(0.056^2 + 0.024^2)^1.5

Q = 7.02 * 10^-7 C

the charge on disk 2 is - 7.02 * 10^-7 C

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