Solve part c , d (10%) Problem 4:1 start walking. The lst leg of my trip I walk

Question

Solve part c , d (10%) Problem 4:1 start walking. The lst leg of my trip I walk dA-125 m at walk dB = 75 m at »-35° north of east. On my final leg I walk dc mat 0c system so that x is directed towards the east, and y is directed towards the north. 3" south of east. The 2nd leg of my trip ! 75° north of west. Choose the coordinate ee 25% Part (a) write an expression for the x component of the final displacement in terms of the given quantities. ve 25% Part (b) Write an expression for the y component of the final displacement in terms of the given quantities. 25% P (c) What is the magnitude of my displacement vector in meters) as measured from the origin? Grade Sum Deductions Potential RI= 25321 IRI= 1253.21 7 8 9 HOME Attempts ren per atte n an acos0 acotan0sinh0 cosh tan0 cotan0 Hint I give up! Hints: 2% deduction per hint. Hints remaining: 2 Feedback:-deduction per feedback. 25% Part (d) what is the angle of my displacement vector as measured north from the + x-axis?

Explanation / Answer

a)

here

Rx = dA * cos(theta A) + dB * cos(theta B ) + dC * cos(theta C)

Rx = 125 * cos(35deg) + 75 * cos(35 deg) + 65 * cos(75deg)

Rx = 180.7 m

b)

Ry = dA * sin(theta A) + dB * sin(theta B) + dC * sin(theta C)

Ry= 125 * sin(35 deg) + 75 * sin(35deg) + 65 * sin(75deg)

Ry = 177.5 m

c)

the resultant magnitude is

R = sqrt( Rx^2 + Ry^2)

R = sqrt( 180.7^2 + 177.5^2)

R = 253.296 m

d)

the angle theta

tan(theta) = Ry / Rx

theta = tan^-1( Ry / Rx)

theta = tan^-1( 177.5 / 180.7)

theta = 44.49 deg

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