(a) Find the time interval required for the proton to travel 6.00 cm horizontall

Question

(a) Find the time interval required for the proton to travel 6.00 cm horizontally.

Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. ns

(b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.)

Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. mm

(c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally

Explanation / Answer

A) time required is t = distance/speed = 0.06/(5.2*10^5) = 115.3 ns

B) accelaation a = F/m = q*E/m = (1.6*10^-19*8.6*10^3)/(1.67*10^-27) = 8239.5*10^8 m/s^2

vertical displacement y = 0.5*a*t^2 = 0.5*8239.5*10^8*(115.3*115.3)*10^-18 = 5.5*10^7*10^-18 = 5.5*10^-11 m = 5.5*10^-8 mm

C) vx = ux = 5.2*10^5 m/s

vy = uy+(a*t) = 8239.5*10^8*115.3*10^-9 = 95001.435 m/s

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