Can you show your answer in writing, it makes it easier for me to understand the

Question

Can you show your answer in writing, it makes it easier for me to understand the step-by-step

An object moves with constant acceleration 3.45 m/s^2 and over a time interval reaches a final velocity of 10.4 m/s. (a)If its initial velocity is 5.2 m/s, what is its displacement during the time interval? 8.26 Your response differs from the correct answer by more than 10%. Double check your calculations. m (b) What is the distance it travels during this interval? 8.26 Your response differs from the correct answer by more than 10%. Double check your calculations. m (C) If its initial velocity is -5.2 m/s, what is its displacement during the time interval? Your response differs from the correct answer by more than 10%. Double check your calculations. m (d) What is the total distance it travels during the interval in part (c)? 3.475 Your response differs from the correct answer by more than 10%. Double check your calculations. m Can you show your answer in writing, it makes it easier for me to understand the step-by-step

Explanation / Answer

given,

acceleration = 3.45 m/s^2

final velocity = 10.4 m/s

if initial velocity is 5.2 m/s then

by third equation of motion

v^2 = u^2 + 2 * a * s

10.4^2 = 5.2^2 + 2 * 3.45 * s

s = 11.7565 m

displacement = 11.7565 m

distance will be same as diaplacement

so,

distance = 11.7565 m

let time interval be t so,

v = u + at

10.4 = 5.2 + 3.45 * t

t = 1.50725 sec

if initial velocity is -5.2 then

s = ut + 0.5 * a * t^2

s = -5.2 * 1.50725 + 0.5 * 3.45 * 1.50725^2

s = -3.919 m

displacement = -3.919 m

distance is scalar so it will be 3.919 m

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.