You are pulling your younger sister along in a small wheeled cart. you weigh 65.

Question

You are pulling your younger sister along in a small wheeled cart. you weigh 65.0 kg. and the combined mass of your sister and the cart is 35.0 kg. YOu are pulling the cart via a short rope which you pull horizontally. You hold one end of the rope and your sister holds the other end. I you are accelerating at a rate of 0.10m/s^2 the rope is inelastic, and the frictional force acting upon the cart is 30 N:

a. What is the tension in the rope?

b. What force are you applying to the ground in order to produce this acceleration?

Explanation / Answer

given,

weight = 65 kg

weight of sister + cart = 35 kg

acceleration = 0.1 m/s^2

frictional force = 30 N

The net force f = mass * acceleration

also,

f = tension - frictional force

so the tension t = mass * acceleration + frictional force

t = 35 * 0.1 + 30

t = 33.5 N

Tension in the rope = 33.5 N

The normal force N = W = Mg produces the friction force F = kN where k is the coefficient of rolling friction.

The normal force is the weight of the cart and sister

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