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iPad 3:53 PM 57% edugen.wileyplus.com yLUGradebook Courses-Blackboard Learn tudy & Practice Assignment Gradebook ORION PRINTER VERSION BACK SOURCES chapter Chapter 03, Problem 23 Your answer is partially correct. Try again. blem 10 As preparation for this problem, review Conceptual Example 10. The drawing shows two planes each dropping an empty fuel tank. At the moment of release each plane has the same speed of 108 m/s, and each tank is at the same height of 2.45 km above the ground. Although the speeds are the same, the velocities are different at the instant of release, because one plane is flying at an angle of 15.0° above the horizontal and the other is flying at an angle of 15.0° below the horizontal. Find the (a) magnitude and (b) direction of the velocity with which the fuel tank hits the ground if it is from plane A. Find the (c) magnitude and (d) direction of the velocity with which the fuel tank hits the ground if it is from plane B. In each part, give the direction as a positive angle with respect to the horizontal. blem 522 blem 7because one blem 25 y Study tank Pane A Plane B (a) Number 283.84 (b) Number-68.44 Units 245.69 (d) Number 83.47 Click if you would like to Show Work for this question: Open Show Work Question Attempts: 1 of S used SAVE FOR LATER Copyright © 2000-2015 by John Wiley & Sons, Inc. or related companies. All rights reserved. Privacy Poicy1 2090-2015 John Wley & Sons Inc. All Rights Reserved. A Division of lohn Wiley & Sons Ins Version 4.16.17Explanation / Answer
for plane A
vox = vo*cos15 = 108*cos15 = 104.32 m/s
voy = + vo*sin15 = 108*sin15 = 27.95 m/s
y = -2.45 km = -2540 m
acceleration a = -9.8 m/s^2
from equation of moption
vy^2 - voy^2 =2*a*y
vy^2-27.95^2 = 2*9.81*2450
vy = 221.03 m/s
magnitude = sqrt(vy^2+vox^2) = 244.41 m/s <<-answer
direction = tan^-1(vy/vox)
direction = 64.74 degrees
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for plane B
vox = vo*cos15 = 108*cos15 = 104.32 m/s
voy = - vo*sin15 = -108*sin15 = -27.95 m/s
y = -2.45 km = -2540 m
acceleration a = -9.8 m/s^2
from equation of moption
vy^2 - voy^2 = 2*a*y
vy^2-27.95^2 = 2*9.81*2450
vy = 221.03 m/s
magnitude = sqrt(vy^2+vox^2) = 244.41 m/s <<-answer
direction = tan^-1(vy/vox)
direction = 64.74 degrees
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