// I only have one more attempt for part B and cannot come up with the correct a

Question

// I only have one more attempt for part B and cannot come up with the correct answer.

// We are using the University Physics 13th ed. and Mastering Physics website. . . NEED HELP with part B.

Problem 17.92:

You cool a 110.0 g slug of red-hot iron (temperature 745 C) by dropping it into an insulated cup of negligible mass containing 75.0 g of water at 20.0 C. Assume no heat exchange with the surroundings.

A.

What is the final temperature of the water?

Express your answer using three significant figures.

Ans: 100 C

B.

What is the final mass of the iron and the remaining water?

Express your answer using three significant figures.

_____?_____ grams

Explanation / Answer

for the part B)

let the mass of water remaining is m gm

specific heat of iron , Si = 0.450 J/gm*C

Now , heat used for boiling the water

Q = 110 * 0.450 * (745 - 100) - 4.186 * 75 * (100 - 20)

Q = 6811.5 J

mass of water boiled using this heat

75 - m = 6811.5/latent heat of vapourization

75 - m = 6811.5/2260

m = 72 gm

Now, mass of water and iron remaining = 72 + 110

mass of water and iron remaining = 182 gm

the final mass of water and iron remaining is 182 gm

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