You have the following items ready to use for making solutions: Glucose (solid;

Question

You have the following items ready to use for making solutions:

Glucose (solid; MW=180g/mol)

1M Tris HCl (liquid solution;MW= 158g/mol )

Acetone (liquid; MW=58g/mol)

10% agarose (liquid solution; MW=631g/mol)

Your instructions state that you need to make 10 ml of 0.25M Tris HCl solution.

Match the following information to prepare to conduct the math required to generate this specific Tris HCl solution. Not all choices will be used.

Answer choices below:

A) Final volume (Vf or V2)

B) Original volume or amount (Vo or V1)

C) Final Concentration (Cf or C2)

D) Original concentration (Co or C1)

N/A - solute source is not in solution

To be determined (your unknown)

1M

500 ml

0.25M

10%

10 ml

A) Final volume (Vf or V2)

B) Original volume or amount (Vo or V1)

C) Final Concentration (Cf or C2)

D) Original concentration (Co or C1)

1.

N/A - solute source is not in solution

2.

To be determined (your unknown)

3.

1M

4.

500 ml

5.

0.25M

6.

10%

7.

10 ml

Explanation / Answer

the formula used for this calculation is -

Original concentration (Co or C1)* Original volume or amount (Vo or V1) = Final Concentration (Cf or C2)* Final volume (Vf or V2).

OR C1* V1 = C2 * V2 where

(Co or C1) = 1M

(Vo or V1) = To be determined (your unknown)

(Cf or C2) = 0.25M

(Vf or V2) = 10 ml

1M * X = 0.25 * 10

X = 0.25*10/1

X = 2.5 ml from 1M Tris HCl solution and 7.5 ml water.

so

A) Final volume (Vf or V2) = option 7. 10 ml

B) Original volume or amount (Vo or V1) = option 2. To be determined (your unknown)

C) Final Concentration (Cf or C2) = option 5. 0.25M

D) Original concentration (Co or C1) = option 3. 1M

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