1- Suppose that a qudratic fit to a position plot yelds the followig fit results
ID: 1406959 • Letter: 1
Question
1- Suppose that a qudratic fit to a position plot yelds the followig fit results:
y = 4.97x2 +1.53x + 0.0503. From this fit result:
A) determine the acceleration due the gravity of the particle.
B) determie the initial velocity of the particle.
2) plot the position of a particle as afunction of time for an object dropped from rest for the time of 0 seconds to 1.2 seconds i time intervals of 0.2 seconds ( a total of seven points)
3) Suppose that the acceleration due to gravity was measured in a free fall expirment to be ( 9.777± 0.252). does this value agree with the ucertainty with the given value for the acceleration due to gravity in Mobile, Alabama?
*( Acceleration Gravity i Mobile,Al g= 9.793394.
Explanation / Answer
1.
y = 4.97x2 +1.53x + 0.0503
a)
taking derivative both side relative to 'x'
dy/dx = 4.97 (2) x + 1.53
taking derivative both side relative to 'x' aagain
d2y/dx2 = 4.97 (2)
a = 9.94 m/s2
b)
Velocity of the particle is given as
V = dy/dx = 4.97 (2) x + 1.53
at X =0
V = 1.53 m/s
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