Coach Sue is making you run hills at practice while the biomechanics class is re

ID: 1407105 • Letter: C

Question

Coach Sue is making you run hills at practice while the biomechanics class is recording

digital video for a lab assignment. The coordinates of your center of mass (COM) at the

bottom of the hill are (3.5 units, 2.1 units) and at the top of the hill they are (21.3 units, 37.6

units). The field of view of the cameras was calibrated to be 1 m = 1.42 units. What is your

displacement after running to the top of the hill 3 times (up, down, up, down, up)? What is

your average resultant velocity if it takes you 16 s to run up the hill one time? (4 pts)

SHOW ALL WORK

Displacement: __________

Average resultant velocity: __________

1 m = 1.42 units

1 unit = 0.7 m

Given initial coordinates x1,y1 = 3.5,2.1 units = 3.5 x 0.7 m , 2.1 x 0.7 m = 2.45 m , 1.47 m

Final coordinates x2,y2 = 21.3, 37.6 units = 21.3 x 0.7 m, 37.6 x 0.7 m = 14.91 m, 26.32 m

Displacement uphill = shortest distance between final position and initial position

shortest distance between final and initial position is d = {(x2-x1)^2 +(y2-y1)^2} = {(14.91-2.45)^2 +(26.32-1.47)^2 = {155.25 +617.5} = 27.8 m

Average velocity = displacement/time = 27.8/16 = 1.74 m/s

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.