Two skydivers are holding on to each other while falling straight down at a comm

Question

Two skydivers are holding on to each other while falling straight down at a common terminal speed of 52.30 m/s. Suddenly, they push away from each other. Immediately after separation, the first skydiver (who has a mass of 89.30 kg) has the following velocity components (with ''straight down'' corresponding to the positive z-axis): v1,x=4.430 m/s v1,y=4.250 m/s v1,z = 52.30 m/s What are the x- and y-components of the velocity of the second skydiver, whose mass is 63.20 kg, immediately after separation?

Explanation / Answer

before separation, momentum along x axis=0

=> momentum along x axis after seprataion=0

==> 89.3*4.43+63.2*V2,x=0

==> V2,x=-6.26 m/s

before sepration, momentum along y axis =0

==> after separation, momentum along y axis=0

==> 89.3*4.25+63.2*V2,y=0

==>V2,y=-6 m/s

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