Use component method to solve Problem 2-34 gnitude of the resultant force acting

Question

Use component method to solve Problem 2-34 gnitude of the resultant force acting the eyebolt is 600 N and its direction measured clock from the positive x axis is 30 determine the magni- tude of FI and the angle d. "2H0. Determine the magnitude and coordinate direction angles of the resultant force acting on the bracket. Fi-450 N Fa-600 N "Student will present and complete Problem 2-112 in class: Monday, September 14 "2-112. Determine the projected component ofthe force Faa S60 Nacting along cable ACExpress the resul as a Cartesian vector. HW PROBLEMS THOMPSON FALL 2015

Explanation / Answer

here

force in x direction

F1x = F1 * cos(theta)

F2x = 500 * cos60deg = 250 N

F3x = 450 * 3 / 5 = 270 N

Frx = 600 * cos(30deg) = 519.62 N

then

along y axis

F1y = F1 * sin(theta)

F2y = 500 * sin(60deg) = 433.01 N

F3y = -450 * 4 / 5 = -360 N

Fry = -600 * sin(30deg) = -300 N

afterthis the resulting force

summing the force components algebraically along x and y

519.62 = F1 * cos(theta) + 250 + 270

F1*cos(theta) = 539.62 N..................(1)

then

-300 = F1 * sin(theta) - 433.01 - 360

F1 * sin(theta) = 493.01 N ................(2)

solving both equations

theta = 42.4 deg

F1 = 731 N

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