During volcanic eruptions, chunks of solid rock can be blasted out of the volcan

Question

During volcanic eruptions, chunks of solid rock can be blasted out of the volcano; these projectiles are called volcanic bombs. The figure shows a cross section of Mt. Fuji, in Japan. (a) At what initial speed would a bomb have to be ejected, at angle 6 = 330 to the horizontal, from the vent at A in order to fall at the foot of the volcano at B, at vertical distance h = 3.10 km and horizontal distance d = 9.70 km? Ignore, for the moment, the effects of air on the bomb?s travel. (b) What would be the time of flight?

Explanation / Answer

Here ,

let the initial speed of the bomb is u

Using equation of trajectory

y = x * tan(theta) - g * x^2/( 2 *(u * cos(theta))^2)

-3100 = 9700 * tan(33) - 9.8 * 9700^2/( 2* ( u * cos(33))^2)

solving for u

u = 264.1 m/s

the initial speed of the bomb is 264.1 m/s

B)

time of flight , tf = 9700/(264.1 * cos(33))

tf = 43.8 s

the time of flight is 43.8 s

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.