Vectors A and B lie in an xy plane. A has magnitude 8.00 and angle 1500; B has c

Question

Vectors A and B lie in an xy plane. A has magnitude 8.00 and angle 1500; B has components B = -8.32 and B = -9.65. (a) What s the angle between the negative direction of the y axis and the direction of A? clockwise from the -y axis (b) What is the angle between the negative direction of the y axis and the direction of the product A x B? (c) What is the angle between the negative direction of the y axis and the direction of A x (B + 3.00 k)? J O counterclockwise and upward (toward + k) from the -y axis

Explanation / Answer

a)

Ax = 8*cos150 = -6.93

Ay 8*sin150 = 4

a)

90+30 = 120

b)

90

c)

A X(B+3i)=

    i      j        k

-6.93     4       0

-8.32    -9.65   3

A X(B+3i) = 12i + 20.79j + 100.15 k

magnitude = sqrt(12^2+20.79^2+100.15^2) = 103

angle between -y & Ax(B+3k) = cos^-1(-20.79/103) = 101.64

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