While living in a high rise apartment and staring out a window, you see a flower

Question

While living in a high rise apartment and staring out a window, you see a flower pot fall past. It takes the flower pot 0.56 seconds to go by your window which is 2.1 meters tall. You assume the flower pot fell from one of your neighbors ledges above you. Calculate the speed the flower pot had at the top of your window Using the results from , and assuming the flower pot was knocked off of its spot from rest above you, calculate how far the flower pot had fallen before you spotted it? If the bottom of your window is 10 meters above the ground, how fast is the flower pot going when it strikes the ground?

Explanation / Answer

let initial speed of the pot at top of your window = u m/s

acceleration due to gravity=9.8 m/s^2

distance covered=2.1 m

time taken =0.56 seconds

using the formula:

distance=initial speed*time+0.5*acceleration*time^2

==>2.1=u*0.56+0.5*9.8*0.56^2

==>u=1.006 m/s

hence the pot had a speed of 1.006 m/s

part b:

assuming it was knocked off at a height of d m from the top of your window,

initial speed =0 m/s

distance covered =d m

final speed=1.006 m/s

using the formula
:

final speed^2-initial speed^2=2*acceleration*distance

==>1.006^2-0^2=2*9.8*d

==>d=0.05163 m

part c:

initial speed at your window=1.006 m/s

distance to ground =10 m

if final speed is v m/s,

then v^2-1.006^2=2*9.8*10

==>v=14.0361 m/s

hence the pot was travelling at 14.0361 m/s when it hit ground.

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