The circuit shown in the figure a used to make a magnetic balance to with object

Question

The circuit shown in the figure a used to make a magnetic balance to with objects The mass m to be measured is hung from the center at the bar. that is in a uniform magnetic field 1.50 T. directed into the plane of the figure. The battery voltage can be adjusted to vary the current in the circuit. The horizontal bar a 60.0 cm long and is made of extremely light-weight material. It is connected to the battery by thin vertical wires that can support no appreciable tension, all the weight of the suspended mass m is supported by the magnetic force on the bar. A resistor with R = 5.00 ohm is in series with the bar; the resistance of the rest of the circuit a much less than this. Which point a or b. should be the positive terminal of the battery? If the maximum terminal voltage of the battery it 175 V. whit is the greatest mass m that this instrument can measure? m = kg

Explanation / Answer

a) To balance the weight mg, magnetic force should be upward and current should be left to right as F = i L x B

So positive terminal of battery is a

b) mg = i L x B

    m*9.8 =175/5 *0.60*1.50

   m = 175/5 *0.60*1.50 / 9.8

      = 3.214 kg

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