A converging lens has a focal length of 20.5 cm. Give the image distance and mag

Question

A converging lens has a focal length of 20.5 cm. Give the image distance and magnification for the following object distances, using the correct sign conventions. Select all options that correctly describe the image. If the image is located at infinity, enter "infinity" for the image distance and for the magnification, and select "no image is formed". (a) object distance = 39.9 cm image distance Correct: Your answer is correct. . cm magnification Correct: Your answer is correct. . real no image is formed side of lens opposite the object virtual inverted upright same side of lens as the object Correct: Your answer is correct. . . (b) object distance = 20.5 cm image distance Incorrect: Your answer is incorrect. . cm magnification Incorrect: Your answer is incorrect. . no image is formed same side of lens as the object side of lens opposite the object inverted upright real virtual Correct: Your answer is correct. . . (c) object distance = 10.8 cm image distance Correct: Your answer is correct. . cm magnification Incorrect: Your answer is incorrect. . Your response differs from the correct answer by more than 10%. Double check your calculations. upright side of lens opposite the object same side of lens as the object virtual real inverted no image is formed Correct: Your answer is correct. . .

Explanation / Answer

using lens formula

1/f = 1/di + 1/do

a)

1/di = 1/20.5 - 1/39.9

distance of image = 42.16 cm

magnification = -di/do = - 42.16/39.9 = - 1.056

image is real and inverted.

b)

1/di = 1/20.5 - 1/20.5

distance of image = infinity

magnification = no image is formed.

c)

1/di = 1/20.5 - 1/10.8

distance of image = - 22.82 cm

magnification = -di/do = - (-22.82)/10.8 = 2.11

image is virtual and upright.

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