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A group of particles is traveling in a magnetic field of unknown magnitude and d

ID: 1408263 • Letter: A

Question

A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.06×1016 N in the +y-direction, and an electron moving at 4.70 km/s in the z-direction experiences a force of 8.30×1016 N in the +y-direction.

A)What is the magnitude of the magnetic field?

B)What is the direction of the magnetic field? (in the xz-plane)

C)What is the magnitude of the magnetic force on an electron moving in the y-direction at 3.70 km/s ?

D)What is the direction of this the magnetic force? (in the xz-plane)

Will rate. Thank you!

Explanation / Answer

A.)

for proton

F = QVB

F = 1.6*10^-19 *1700 *B

2.06*10^-16 = 1.6*10^-19 *1700 *B

B = 0.757 T

for electron

F = QVB

F = -1.6*10^-19 *4700 *B

8.3*10^-16 = 1.6*10^-19*4700*B

B = 1.103 T

B.) for proton: -z axis(downward) according to right hand thumb rule.

for electron :( - x axis)

C.)

F = QVB

F = 1.6*10^-19 *3700 *1.103

F = 6.53*10^-16 N

D)+ Z axis (upward)

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