Find the average velocity over the whole time shown. Answer in units of m/s. A c

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Find the average velocity over the whole time shown. Answer in units of m/s. A car travels along a straight stretch of road. It proceeds for 11.2 mi at 50 mi/h, then 21.1 mi at 48 mi/h, and finally 37.7 mi at 30.8 mi/h. What is the car's average velocity during the entire trip? Answer in units of mi/h. A ball is dropped from rest at point O. After falling for some time, it passes by a window of height 3.6 m and it does so in 0.24 s. The ball accelerates all the way down; let va be its speed as it passes the window's top A and vb its speed as it passes the window's bottom B. How much did the ball speed up as it passed the window; i.e., calculate Deltaupsilon_down = upsilon_B-upsilon_A ? The acceleration of gravity is 9.8 m/s^2. Answer in units of m/s. Calculate the speed upsilon_A at which the ball passes the window's top. Answer in units of m/s. Now consider a new situation: The ball is thrown upward from the ground with an initial velocity that takes exactly the same time t_BA = t_AB = 0.24 s to pass by the window, with the ball moving up rather than down. Consider the ball's slowdown during this time: Let upsilon_B' be the ball's speed (do not confuse the speed with the velocity) as it passes the window's bottom on the way up and let upsilon_A' be its speed as it passes the window's top, also in its way up. How does the ball's slowdown Deltaupsilon_up = upsilon_B' - upsilon_A' compare to its speedup Deltaupsilon_down on the way down? 1. Deltaupsilon_up > Deltaupsilon_down if the mass of the ball is less than 0.1 kg and Deltaupsilon_up

Explanation / Answer

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Q25.

To do problems like these, you need just one simple rule:
Average speed = (total distance traveled) / (travel time)
... or ...
v[ave] = x/t

You've got 3 legs to the trip, and for each one, a distance and speed are given; use the rule to find the 3 times:
t = x/v
t = x/v
t = x/v

Then use it once more to get the overall trip's average speed:
v[ave] = x/t = (x + x + x)/(t + t + t)

Your final result will be
v[ave] = (11.2 + 21.1 + 37.7) mi / (11.2/50 + 21.1/48 + 37.7/30.8) h
= 70 mi / 1.887609 h
= 37.08 mi/h

and because a velocity is asked for, this requires a direction, which is just the direction of travel along that straight road.

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