5.In a 290-turn automobile alternator, the magnetic flux in each turn is B = 2.5
ID: 1408548 • Letter: 5
Question
5.In a 290-turn automobile alternator, the magnetic flux in each turn is B = 2.50 10-4 cos t, where B is in webers, is the angular speed of the alternator, and t is in seconds. The alternator is geared to rotate four times for each engine revolution. The engine is running at an angular speed of 1.00 103 rev/min.
(a) Determine the induced emf in the alternator as a function of time. (Assume e m f is in V.) e m f = ______
(b) Determine the maximum emf in the alternator. __________V
1.A 27-turn circular coil of wire has diameter 0.95 m. It is placed with its axis along the direction of the Earth's magnetic field of 53.0 µT and then in 0.200 s is flipped 180°. An average emf of what magnitude is generated in the coil? __________mV
Explanation / Answer
(a)
= 4 * 1000 * (2*)/60 rad/s
= 418.8 rad/s
e = -N*d/dt (B)
e = - 290 * d/dt (2.50*10^-4 cos(t))
e = 290 * 2.50 * 10^-4 ** sin(t)
e = 290 * 2.50 * 10^-4 *418.8* sin(418.8*t)
e = 30.36 * sin(418.8*t)
(b)
From the above equation,
Maximum emf, e = 30.36 V
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