Help with physics impulse-momentum. Please show all work. Thank you! Imagine a b

Question

Help with physics impulse-momentum. Please show all work. Thank you!

Imagine a ball of mass 0.2 kg is thrown against a surface (of unspecified orientation!) with speed v of 25 m/s and at an angle 0 of 70 degrees with the surface. Assuming it bounces off (within a time interval of 0.01 s) with the same speed and at the same angle (but on the other side of the normal to the surface of course), what is the approximate value of the average force exerted by the ball on this surface? For full credit, you need to explain what you are doing, by specifying the system of interest, the interaction of interest, and by justifying the equations used and the way you simplify them, if applicable!

Explanation / Answer

Since only normal component of the velocity changes,

Change in momentum = 0.2*25*(sin 70 degree - -sin 70 degree)

= 9.397 kg m/s

This change in momentum is offered by impulse by the surface

Impulse offered by the surface = F*t

9.397 kg m/s = F *0.01

F = 939.7 N

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