Please show detailed work Gliese 581 is a red dwarf, host to the first discovere

Question

Please show detailed work

Gliese 581 is a red dwarf, host to the first discovered Earth-like exoplanets. It radiates about 1.30% of our sun's electromagnetic power. The average intensity of the Sun on Earth is 1370 W/m. Knowing that the Sun is 1.49 middot 10^11 m from Earth, what is the power radiated by Gliese 581? Australia's Parkes radio telescope has a dish (consider it as a disk) with a 64 m diameter. When pointed towards the Gliese 581 system, it receives 30.2 nW of electromagnetic radiation through the entire area of the dish. By calculating the corresponding intensity received, estimate how far Gliese 581 is from Earth. Give your answer in light-years (1 ly ~ 9.46 moddot 10^15m)

Explanation / Answer

1) Here, intensity on Sun surface = 1370 * (1.49 * 1011)2/(695700000)2

                                                                            =   6.2841 * 107   W/m2

=> power radiated by Gliese = 0.013 * 6.2841 * 107 * 4 * 3.14 * (695700000)2

                                                                      = 4.9661 * 1024 W

2)    Distance of Gliese from Earth =   sqrt [(4 * 3.14 * 32 * 32 *0.013 * 6.2841 * 107)/(30.2 * 10-9)] * 1.49 * 1011

                                                                                  = 8.7886 * 1019 m

                                                       =   9290.3 ly

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.