Help with Physics Impulse and Moment. Please show all your work and explain your

Question

Help with Physics Impulse and Moment. Please show all your work and explain your steps. A diagram would also be helpful. Thank you.

with Imagine a ball of mass 0.2 kg is thrown against a surface (of unspecified orientation!) speed v of 25 m/s and at an angle of 70 degrees with the surface. Assuming it bounces off (within a time interval of 0.01 s) with the same speed and at the same angle (but on the other side of the normal to the surface of course), what is the approximate value of the average force exerted by the ball on this surface? For full credit, you need to explain what you are doing, by specifying the system of interest, the interaction of interest, and by justifying the equations used and the way you simplify them, if applicable!

Explanation / Answer

As the angle with the surface is 70, the angle witht the normal will be 20 degree.

We also know that as the ball returns at the same angle to the normal with the same velocity. The only change is in the component along the normal not the horizontal one.

Hence we can write the change in the momentum as

P = m (Vy + Vy) = 47 kgm/s

Now using newton's second law

F = dP/dT = 47/o.o1 = 4700 N

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