During a lightning discharge, 30 C of charge move through a potential difference

Question

During a lightning discharge, 30 C of charge move through a potential difference of 1.0 Times 10^3 V in 2.0 Times 10^-1 s. The energy released by this lightning bolt is: 1.5 Times 10^41 J 3.0 Times 10^9 J 6.0 Times 10^7 J 3.3 Times 10^4 J 1500 J Electric power is equal to current Times voltage current/voltage resistance Times voltage voltage/currcnt The voltage needed to produce a current of 5 A in a resistance of 40 Ohm is. 1.25 V 5 V 8 V 200 V A battery of cmf 24 V is connected to an 11-Ohm resistor. If the current in the circuit is 2 amps, the internal resistance of the battery is 0.5 Ohm 1 Ohm 2 Ohm 4 Ohm Three 5-Ohm resistors are connected in parallel across a 10 V battery. The current in each resistor is 0.67 A 2 A 5 A 6 A A 2-pico farad and a I pico farad capacitor are connected in series and a potential difference is applied across the combination. The 2 pico farad capacitor has: twice the charge of the I-pF capacitor half the charge of the 1-pF capacitor twice the potential difference of the 1-pF capacitor

Explanation / Answer

22) Since we know that v = J/C

   J = V * C

= 30C * 1.0 * 10^4 V

   = 3.0 * 10^5V

23 ) electric power = current * voltage

a) current * voltage

24) voltage = I * R

= 5 * 40

= 200 V

25) E = V - Ir

   internal resistance E =

   = 24 - 11(2)

   = 2 ohms

26) as we know that current I = V/R

   = 10/5

   = 2A

Therefore current in each resistor is 2A

  

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